【高分必看】GMAT逻辑难题应对方法解题思路步骤实例精讲

GMAT逻辑考的是思维能力，这点人人都知道。但优秀的逻辑推理能力却并非人人具备。想要在GMAT逻辑部分中表现出色，考生就必须学会正确运用自己的推理来打开解题思路。下面小编就通过1道高难度的GMAT逻辑题，来为大家实例解析其中涉及到的逻辑推理思路。

GMAT高难度逻辑真题实例解析

In Patton City, days are categorized as having heavy rainfall (more than two inches),moderate rainfall (more than one inch, but no more than two inches), light rainfall (at least a trace, but no more than one inch), or no rainfall. In 1990, there were fewer days with light rainfall than in 1910 and fewer with moderate rainfall, yet total rainfall for the year was 20 percent higher in 1990 than in 1910.

If the statements above are true, then it is also possible that in Patton City

A. the number of days with heavy rainfall was lower in 1990 than in 1910

B. the number of days with some rainfall, but no more than two inches, was the same in 1990 as in 1910

C. the number of days with some rainfall, but no more than two inches, was higher in 1990 than in 1910

D. the total number of inches of rain that fell on days with moderate rainfall in 1990 was more than twice what it had been in 1910

E. the average amount of rainfall per month was lower in 1990 than in 1910

思路分析：

已知：heavy rainfall > 2 inches; 2 >= moderate rainfall > 1; 1 >= light rainfall > 0。 而且1990年小雨和中雨的天数都比1910少，然而1990年全年的降雨量还比1910多，那就只能是1990年的大雨天数比1910多，一般我们都会这样的预估，但选项恰恰没有该项。迷茫中，看到了D，误以为找到了救星，正好落在了出题者的陷阱之中。

细看该题所问“If the statements a above are true, then it is also possible that in Patton City”，注意到possible这个词。原来并非是由原文推出选项的导出题，而是一道怪题;只要是“可能的”项就是正确的。换句话说，依据原文，有四个选项是绝不可能的，只有一个是可能的。

那再看D，在1990年中雨天数比1910少的情况下，其降雨量可以超过1910的2倍吗?绝不可能 ------ 因为2>=moderate rainfall > 1，即最大的中雨量不超过最小的中雨量的2倍，也就是：即便1990的中雨天每次都是最大量，而1910的中雨量每次都是最小量，那么D都不能成立。

而B与C明显与已知条件矛盾(“1990年小雨和中雨的天数都比1910少”)。同时E与“1990年全年的降雨量还比1910多”冲突。看来也就A有希望了;但A与我们的预估相反。

但A的确是可能的，这一点可以举一个最极端的情况，1990年只下了一天雨，那是一场万年不遇的亿寸豪雨，其降雨量可以远远超过1910年的天天小雨、中雨或大雨。一天就超过365天这有什么不可能的呢?

通过以上这道解题思路比较奇怪的高难度真题，相信大家对于如何运用推理和分析思维能力解答GMAT逻辑题也有了一些体悟。分析所有的可能性，找到逻辑中存在的漏洞，这才是GMAT逻辑解题的关键所在。